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共2个回答
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wittyman
丨Lv 3
(x^3+y^3)-(x^2y+xy^2)=(x+y)(x^2-xy+y^2)-xy(x+y)=(x+y)(x^2-2xy+y^2)=(x+y)(x-y)^2x>0,y>0所以x+y>0,(x-y)^2≥0(x+y)(x-y)^2≥0所以x^3+y^3≥x^2y+xy^2
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冰印
丨Lv 3
x^3+y^3=(x+y)*(x^2-xy+y^2)x^2y+xy^2=xy(x+y)(x+y)*(x^2-xy+y^2)-xy(x+y)=(x+y)*(x^2-xy+y^2-xy)=(x+y)*(x-y)^2因为x>,y>0,所以(x+y)*(x-y)^2大于0,即x^3+y^3大于x^2y+xy^2
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